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$\mathbf{\pi} = 3.1415926 \pi \alpha$

$\pi = 3.14$ $\pi \alpha \beta \sigma$

可得 $x^2-2x=0$

可得 $x_i+2x-1=0 +\dfrac34$ 有

公式测试 $x^2+\dfrac{x}{3\sqrt 7} = \sum \limits ^7 _{i=1} k_i.$

二级标题

三级标题

• 列表测试 1
• 列表测试 2
• 列表测试 3
• 列表测试 4

这是引用

$ x^2-2x+1 $ 公式两边不要打空格，否则就无法渲染

$$A = \begin{bmatrix} a_{11} & a_{12} & ... & a_{1n}\\ a_{21} & a_{22} & ... & a_{2n}\\ a_{31} & a_{22} & ... & a_{3n}\\ \vdots & \vdots & \ddots & \vdots\\ a_{n1} & a_{n2} & ... & a_{nn}\\ \end{bmatrix} , b = \begin{bmatrix} b_{1} \\ b_{2} \\ b_{3} \\ \vdots \\ b_{n} \\ \end{bmatrix}$$

$$x^2-2x-\dfrac12=9 \pi .$$

$$\mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \frac{\partial X}{\partial u} & \frac{\partial Y}{\partial u} & 0 \\ \frac{\partial X}{\partial v} & \frac{\partial Y}{\partial v} & 0 \\ \end{vmatrix}$$

$$\begin{gather} \begin{split} Adv^{Fed} & = Pr^{Fed}\left ( A=1\mid x\in D_{T} \right ) - Pr^{Fed}\left ( A=1\mid x\in D_{N} \right ) \\ & = \underset{x\in D_{T}}{E^{Fed}}\left ( P\left ( A=1\mid x \right ) \right )-\underset{x\in D_{N}}{E^{Fed}}\left ( P\left ( A=1\mid x \right ) \right ) \\ & = \underset{x\in D_{T}}{E^{Fed}}\left ( 1-\frac{L\left ( \left ( x,y \right ),F \right )}{A} \right )-\underset{x\in D_{N}}{E^{Fed}}\left ( 1-\frac{L\left ( \left ( x,y \right ),F \right )}{A} \right )\\ & = \frac{1}{A}\cdot \left [ \underset{x\in D_{N}}{E^{Fed}}\left ( L\left ( \left ( x,y \right ),F \right )\right )-\underset{x\in D_{T}}{E^{Fed}}\left ( L\left ( \left ( x,y \right ),F \right ) \right ) \right ] \\ \end{split} \end{gather}$$

这是超链接测试。

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